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Quarttt Posted 21 years ago
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If GIBE-FADE=81, then DICE-CEDE=

A. 53. B. 54. C. 55. D. 56.
  

Top answer

Hi i think the answer is 56........ Here's how GIBE-FADE=81, then DICE-CEDE= 56 If you transfer each letter, of each word to a number as in the alphabet A=1 B=2 etc........ Then the word GIBE gives 7925 and FADE gives 6145 So from 7925 - 6145 square each seperate number to give.....

  • Hi i think the answer is 56........
  • Here's how GIBE-FADE=81, then DICE-CEDE= 56 If you transfer each letter, of each word to a number as in the alphabet A=1 B=2 etc........
  • Then the word GIBE gives 7925 and FADE gives 6145 So from 7925 - 6145 square each seperate number to give.....
  • (49+81+4+25) - (36+1+16+25) now do each sum to give..............
  • ( 159) - ( 78) which gives 81.
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7 Answers
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Hi i think the answer is 56........

Here's how GIBE-FADE=81, then DICE-CEDE= 56

If you transfer each letter, of each word to a number as in the alphabet A=1 B=2 etc........

Then the word GIBE gives 7925 and FADE gives 6145

So from 7925 - 6145 square each seperate number to give.....

(49+81+4+25) - (36+1+16+25) now do each sum t
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good for you, he he Emotion: big smile i don't have the patience to do this
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D I C E C E D E

4 9 3 5 3 5 4 5

-----------------------------------------

4 9 3 5

5 4 5 3 (inverse CEDE)

-----------------------------------------

4*5 = 20

9+4 = 13

3+5 = 8

5*3 = 15

-----------------------------------------

20 + 13 + 8 + 15 = 56
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Transfer each letter by his ordering numeric value (A=1, B=2 ... Z=26)

G I B E F A D E D I C E C E D E

7 9 2 5 6 1 4 5 4 9 3 5 3 5 4 5

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7 9 2 5 4 9 3 5
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QuartttIf GIBE-FADE=81, then DICE-CEDE=
A. 53. B. 54. C. 55. D. 56.

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