[=SDC=] Q73: Sour Grapes

Maria Conlon filted:
[nq:1]Question 73: C6H12O6 -> CH3CH2OH + CO2 CH3CH2OH + O2 -> CH3COOH + H2O CH3COOH -> S/s=s, where S=(-1), therefore s=?-1 (The ? signifies a square-root.) Why?[/nq]
Vinegar is imaginary?...r

[nq:1]Question 73: C6H12O6 -> CH3CH2OH + CO2[/nq]
Does it? It's a long time since I studied chemistry, and I know the law of conservation of mass has been abolished, but...
[nq:1]CH3CH2OH + O2 -> CH3COOH + H2O[/nq]
Not if you drink it quickly enough, it doesn't!
[nq:1]CH3COOH -> S/s=s, where S=(-1), therefore s=?-1 (The ? signifies a square-root.) Why? (Thanks again to Mic

[nq:1]Question 73: C6H12O6 -> CH3CH2OH + CO2 CH3CH2OH + O2 -> CH3COOH + H2O CH3COOH -> S/s=s, where S=(-1), therefore s=?-1 (The ? signifies a square-root.) Why?[/nq]
Note from Panel Member: I goofed on numbering. This one is okay; the other Q73 is actually Q74.
Sorry...
Maria Conlon

[nq:1]Maria Conlon filted:[/nq]
[nq:2]Question 73:[/nq]
(with the first equation balanced)
[nq:2]C6H12O6 -> 2 CH3CH2OH + 2 CO2glucose -> ethanol + carbon dioxide[/nq]
(Anerobic respiration (e.g. in the final stages of yeast fermentation))
[nq:2]CH3CH2OH + O2 -> CH3COOH + H2Oethanol + oxygen -> acetic acid + water[/nq]
(production of vinegar/acetic acid by bacter

(Email Removed) wrote, in part:
[nq:1]C6H12O6 -> CH3CH2OH + CO2 CH3CH2OH + O2 -> CH3COOH + H2O CH3COOH -> S/s=s, where S=(-1), therefore s=?-1 (The ? signifies a square-root.) Why?[/nq]
Thinking aloud, and hoping this'll help someone else (it hasn't helped me): Where do we find S used to signify -1, or s to signify i? Or, best of all, both? (Nowhere that I know of.)
Michael Ha

[nq:2]C6H12O6 -> CH3CH2OH + CO2 CH3CH2OH + O2 -> CH3COOH + H2O CH3COOH -> S/s=s, where S=(-1), therefore s=?-1 (The ? signifies a square-root.) Why?[/nq]
[nq:1]Thinking aloud, and hoping this'll help someone else (it hasn't helped me): Where do we find S used to signify -1, or s to signify i? Or, best of all, both? (Nowhere that I know of.)[/nq]
All I can think of is particle phys

[nq:2]Question 73: C6H12O6 -> CH3CH2OH + CO2[/nq]
[nq:1]Does it? It's a long time since I studied chemistry,[/nq]
Me too. I got a good A-Level in it, astonishingly enough, but all I remember about Chemistry is Mr Marsden's First Law: Soft Southerners use Shaving Foam and Deodorant, Real (which is to say, Northern) Men use Neither. Perhaps even more astonishingly, I have been a Real Man

Although a panel of impartial, scientific observers
[nq:1]would certainly conclude that Mr Marsden was a Professional Northerner (and a fine teacher) I believe that they would fail to agree about whether I smell horrible.[/nq]
Oh, if they were chemists, then "horrible" wouldn't come into it. The question would be, do you smell interesting?
Rather like dogs, I suppose - except that dogs

[nq:1]All I can think of is particle physics. Not something I know much about, but a strange quark is sometimes ... come in**, though, or what that might have to do with vinegar, I have no idea - it seems unlikely.[/nq]
I'm thinking of something like a pun on ACET ONE. An ace is another kind of one. None of the Ts in my dictionary offered me any solace, though.

Peardrops, toujours pea

[nq:1]I'm thinking of something like a pun on ACET ONE. An ace is another kind of one. None of the Ts in my dictionary offered me any solace, though.[/nq]
But isn't acetone CH3COCH3? CH3COOH is acetic acid, aka:

Acetic acid (aqueous)
Acetic Acid, Glacial
Ethanoic acid
Ethanoic Acid Monomer
Ethylic Acid
Glacial acetic acid (pure compound)
Methanecarboxylic acid