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Myvi Posted 14 years ago
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However this method solved higher order BBVs with reducing it to an equivalent system of first order BBVs and advanced the solutions at one point at each step as which will involve more computational time.
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However , this method solved higher order BBVs by reducing them to an equivalent system of first order BBVs and advancing the solutions at one point per step, which involved more computational time.
- However , this method solved higher order BBVs by reducing them to an equivalent system of first order BBVs and advancing the solutions at one point per step, which involved more computational time.
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However, this method solved higher order BBVs by reducing them to an equivalent system of first order BBVs and advancing the solutions at one point per step, which involved more computational time.
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