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Romeorobles Posted 21 years ago
Jokes, Puzzles & Riddles

Mathematical operations

0 Hi guys. 02br
00can you resolve this igualations using only mathematical signs? 02br
02br
001 1 1 = 6 02br
002 + 2 + 2 = 6 02<-- example
003 3 3 = 6 02br
004 4 4 = 6 02br
005 5 5 = 6 02br
006 6 6 = 6 02br
007 7 7 = 6 02br
008 8 8 = 6 02br
009 9 9 = 6 02br
02br
00good luck 0-
  

Top answer

0 Only these two, alas: 02br 02br 00(3x 3) -3 = 6 02br 02br 007 - (7 :7) = 6 0-

— Pieanne

  • 0 Only these two, alas: 02br 02br 00(3x 3) -3 = 6 02br 02br 007 - (7 :7) = 6 0-
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10 Answers
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0 Only these two, alas: 02br
02br
00(3x 3) -3 = 6 02br
02br
007 - (7 :7) = 6 0-
0
0
0 Another: 02br
00(5 - 5) + 5 = 6 0-
0
0
0 And this: 02br
007 - ( 7 : 7) = 6 02br
00OK, I had already done it, sorry! 0-
0
0
0 Ok here's my twopenneth 02br
02br
00 111 can be re- arranged to give VI = 6 (roman numerals) 02br
02br
00 222 already done. 02br
02br
00 333 (3x3)-3 =6 02br
02br
00 444 cant do the symbol but square root of 4 + square root of four + square root of four =6 02br
02br
00 555 5 / 5 +5 =
0
0
0 Hey i think i got the 9 one 02br
02br
00 Here goes ....... 02br
02br
00 999, square root 9 X square root 9 - square root of 9 02br
02br
00 gives 3 x 3 -3 = 6 02br
02br
00 Howzat!!!!!!!!!!!!!!!!!!!!! 0-
0
0
0 Let's do it differently 02br
02br
00(1+1+1)!=6 Factorial: 3! = 1 x 2 x 3 02br
002+2+2=6 02br
003x3-3=6 02br
00sqrt(4)(4)(4)=6 02br
005+5/5=6 02br
006x6/6=6 02br
007-7/7=7 02br
00[sqrt(8)]+[sqrt(8)]+[sqrt(8)]=6 02br
00sqrt(9)(9)(9)=6 02br
02br
00[ ... ] is the
0
0
5000 And I'm right-handed!010id7
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0
0 For 9 9 9 = 6. 02br
02br
00(Sq. root of 9 + Sq. root of 9 ) modulo 9 = 6 0-
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0
0 I like Guest's responses, but I would suggest a more straghtforward solution for 8s: 02br
02br
008-sqrt(sqrt((8+8)))=6 0-
0
0
0(cube root of 8)+(cube root of 8)+(cube root of 8)=6050010id5
0

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