The two variables are "A" and "B," and "A2," "B1," "B2," and "B3" are values assigned to them? " - A.
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AvangiI don't understand your conclusion,No wonder, as I have omitted why I have drawn that conclusion (in case you it is of any interested, it was based on this ).
TanitThe map also puts in evidence that there is no significant correlation between the two variables, as neither does any combination clearly prevail over/dominate the others, nor is any combination outweighed/dominated by the others.Hi, Tanit.
AvangiMy thought was to keep your original up to "variables," and then reword from there:Gosh! I feel dumb!
CalifJimI'd say that adding another clause that says the same thing again (or, to be exact, is deducible from the first clause) is unnecessary.Hi, Jim.
TanitMy example was only an oversimplification of the variables and their values.Thanks for the reference article. I studied it a bit, but it's not my cup of tea.
AvangiI'm not sure if you're sayiing that "no combination prevails" may be deduced from "there is no significant correlation"; or that "no combination has significantly fewer combinations than the others" may be deduced from "no combination prevails"?The latter. Note how much shorter my version is, and you'll see which clause I omitted as (in my opinion) unn
CalifJimA little off-topic: Won't you need something more rigorous statistically than just eye-balling the data and saying that it looks to you like no combination prevails over the others?Sorry, I didn't make it clear that I didn't draw that conclusion by looking at the data.
CalifJimI believe that my version also implies the "nor" clause in Tanit's version -- though I recognize the possibility that some logician may be able to prove me wrong on that point!
To me, both the active version in the "neither" clause and the passive version in the "nor" clause amount to the same thing, namely, all combinations occur in about the same frequency.