49 dogs

It depends on how many medium-sized dogs there are.

From 49 dogs entered in the contest, there are 36 more small dogs than large dogs. The answer is rhetorical, its written into the question itself. x is to find how many large dogs there are. 49 competitors and 36 are not large. x=49 (competitors) -36 (small dogs) = 13 (large dogs). The question isn't about x though, they just want to know how many are small dogs. This is given to you in the equa

7.5 and logical tell you that there aren't half dogs but I get the picture

mango piano 871

There are 49 dogs signed up to compete in the dog show.

Assuming that all the dogs signed up to compete are either 'large' (L) or 'small' (S), then

[ 1 ] L + S = 49.

mango piano 871There are 36 more small dogs than large dogs signed up to compete.

So S is bigger than L (by 36). To get t

Based on the given problem statement, there is apparently no single answer to this, but rather, 7 possible answers. What is definite is that there are small dogs in the show (at least 36) and other dogs, neither large nor small, in odd numbers only. And also that there may be large dogs, not more than 6. The following are the 7 possible situations; the first number is the no. of large dogs