0
Bulenteren Posted 21 years ago
Jokes, Puzzles & Riddles
1+2+3+...+100
0 what is the shortest way to solve this question: 02 br
02 br
00 1+2+3+.....+100=? 02 br
02 br
00 .n.(n+1)/2 except for the solution using this formula please 0-
02 br
00 1+2+3+.....+100=? 02 br
02 br
00 .n.(n+1)/2 except for the solution using this formula please 0-
Top answer
Hi bulenteren The total is 5050 The numbers can be rearranged into pairs, add them like this: (1 + 100) + (2 + 99) + (3 + 98) + . . + (50 + 51) = ?
- Hi bulenteren The total is 5050 The numbers can be rearranged into pairs, add them like this: (1 + 100) + (2 + 99) + (3 + 98) + .
- .
- + (50 + 51) = ?
- If you notice every pair of numbers adds up to 101.
- There are 50 pairs of numbers, so the answer is 50 x 101 = 5050.
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2 Answers
0
Hi bulenteren The total is 5050
The numbers can be rearranged into pairs, add them like this:
(1 + 100) + (2 + 99) + (3 + 98) + . . . . + (50 + 51) = ?
If you notice every pair of numbers adds up to 101. There are 50
pairs of numbers, so the answer is 50 x 101 = 5050.
In general to find the sum of all the numbers from 1 to N:
The numbers can be rearranged into pairs, add them like this:
(1 + 100) + (2 + 99) + (3 + 98) + . . . . + (50 + 51) = ?
If you notice every pair of numbers adds up to 101. There are 50
pairs of numbers, so the answer is 50 x 101 = 5050.
In general to find the sum of all the numbers from 1 to N:
00
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